Any room or capacity has a certain volume. Moreover, even if the premises or containers are empty, this does not mean that they are absolutely empty - their volume is filled with air. That is, determining the volume of air at atmospheric pressure is reduced to calculating the volume of a container or room. If we are talking about determining the mass of air in a certain volume under normal conditions, it is necessary to use Avogadro's law.
Necessary
- - roulette,
- - calculator,
- - a reference book on physics,
- - a reference book on mathematics.
Instructions
Step 1
Air is a mixture of water vapor, oxygen, nitrogen, argon, carbon dioxide. In addition, neon, methane, helium, krypton, hydrogen, xenon are present in the air. However, since the content of all these gases in the air is less than 0.01%, they are usually not mentioned when speaking about the composition of the air. But the fact that air is a mixture of gases suggests that, depending on temperature and pressure, different components of the air do not behave the same. In other words, depending on pressure and temperature, the percentage composition of the air (in the mountains, for example, there is less oxygen in the air) and the content of water vapor (air humidity) in it. In addition, other factors affect the composition of the air: in cities there is more carbon dioxide than in forests, in swampy areas there is more methane, and so on.
Step 2
Measure the geometric dimensions of the room or tank. Depending on the shape of the container or room, length, width, height and diameter may be required.
Step 3
Use a reference book on mathematics: substitute the obtained values into the formulas for calculating the volume of geometric bodies.
Step 4
Calculate with a calculator or in your head. The results obtained will determine the amount of air in rooms or containers.
Step 5
Substitute the resulting volume value in the proportion based on Avogadro's law. 1 mole of air weighs 0, 028 kg and takes a volume of 22, 4 liters. This means that the mass of air in a certain volume V will be equal to the product of the value of this volume in liters and the molar mass (0, 028 kg), divided by the molar volume of gas (22, 4 liters).
